Nandita Agarwal

University Of Iowa
Gme Resident

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Nandita Agarwal Overview

Nandita Agarwal in 2016 was employed at University Of Iowa and had a reported pay of $1,028, according to public records.

University Of Iowa records show Nandita Agarwal held two jobs from 2016 to 2022. From 2016 to 2020 Nandita Agarwal held job of Gme Resident.

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Key Data

Year2016
Full NameNandita Agarwal
Original Job TitleGme Resident 1
Job TitleGme Resident
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StateIowa
EmployerUniversity Of Iowa
Total Pay $1,028

*Information may include where available: salary, bonuses, benefits, retirement contributions, pensions, and other financial data.

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Employer

Employer NameUniversity Of Iowa
Year2016
Number of Employees23,032
Average Annual Wage$60,223
Median Annual Wage$50,252
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Other records for Nandita Agarwal

 (2022)
Fellow Physician Accredited
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 (2021)
Fellow Physician Accredited
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 (2020)
Gme Resident
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 (2019)
Gme Resident
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 (2018)
Gme Resident
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 (2017)
Gme Resident
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Highest Paid with the Same Job Title (Gme Resident)

Co-Workers

 (2016)
Nursing Assistant at University Of Iowa
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 (2016)
Temp Prof Short Term Monthly at University Of Iowa
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 (2016)
Temp Professional Employee at University Of Iowa
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 (2016)
Support Services Specialist at University Of Iowa
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 (2016)
Adjunct Instructor at University Of Iowa
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 (2016)
Temp Professional Employee at University Of Iowa
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 (2016)
Helper at University Of Iowa
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 (2016)
Temp Professional Employee at University Of Iowa
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 (2016)
Temp Professional Employee at University Of Iowa
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 (2016)
Temp Professional Employee at University Of Iowa
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