City of Jacksonville
David Bryant F II in 2020 was employed at City of Jacksonville and had a reported pay of $40,466, according to public records. This pay was 53 percent higher than the average and 61 percent higher than the median salary in City of Jacksonville.
| Year | 2020 |
| Full Name | David Bryant F II |
| Job Title | N/A |
| State | Alabama |
| Employer | City of Jacksonville |
| Annual Wage | $40,466 |
| Pay Plan |
*Information may include where available: salary, bonuses, benefits, retirement contributions, pensions, and other financial data.
| Employer Name | City of Jacksonville |
| Year | 2020 |
| Number of Employees | 237 |
| Average Annual Wage | $26,474 |
| Median Annual Wage | $25,209 |
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