John Hacker E

Huntington County (Huntington)
Council Member

View John Hacker E Background Search

John Hacker E Overview

John Hacker E in 2018 was employed at Huntington County (Huntington) and had a reported pay of $4,104 according to public records.

Huntington County (Huntington) records show John Hacker E held job of Council Member from 2015 to 2018.

In year 2018 John Hacker's salary was 6 percent lower than average Council Member salary in the state of Indiana.

Advertisement

Key Data

Year2018
Full NameJohn Hacker E
Job TitleCouncil Member
Get Council Member Salary Statistics
StateIndiana
EmployerHuntington County (Huntington)
Total Pay $4,104

*Information may include where available: salary, bonuses, benefits, retirement contributions, pensions, and other financial data.

Advertisement

Employer

Employer NameHuntington County (Huntington)
Year2018
Number of Employees284
Average Annual Wage$37,876
Median Annual Wage$36,986
View John Hacker E Background Search

Other records for John Hacker E

 (2017)
Council Member
View Person Details
 (2016)
Council Member
View Person Details
 (2015)
Council Member
View Person Details
Find More

Highest Paid with the Same Job Title

Co-Workers

 (2018)
Maintenance Summer Help at Huntington County (Huntington)
View Person Details
 (2018)
Jailer at Huntington County (Huntington)
View Person Details
 (2018)
Part Time Cook at Huntington County (Huntington)
View Person Details
 (2018)
Program Aid Part Time at Huntington County (Huntington)
View Person Details
 (2018)
Part Time Jailer at Huntington County (Huntington)
View Person Details
 (2018)
Secretary at Huntington County (Huntington)
View Person Details
 (2018)
Security Officer at Huntington County (Huntington)
View Person Details
 (2018)
Caseworker at Huntington County (Huntington)
View Person Details
 (2018)
Med Death Investigator at Huntington County (Huntington)
View Person Details
 (2018)
Med Death Investigator at Huntington County (Huntington)
View Person Details
Show All Employees of Huntington County (Huntington)
Advertisement