Osceola County
Hensley Steven in 2019 was employed at Osceola County and had an annual salary of $58,553, according to public records. This salary was 7 percent higher than the average and 10 percent higher than the median salary in Osceola County.
| Year | 2019 |
| Full Name | Hensley Steven |
| Job Title | N/A |
| State | Florida |
| Employer | Osceola County |
| Annual Wage | $58,553 |
*Information may include where available: salary, bonuses, benefits, retirement contributions, pensions, and other financial data.
| Employer Name | Osceola County |
| Year | 2019 |
| Number of Employees | 1,570 |
| Average Annual Wage | $54,759 |
| Median Annual Wage | $53,453 |
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