Seminole County
Firefighter
Johnston Harry in 2019 was employed at Seminole County and had a reported pay of $47,171, according to public records. This pay was 11 percent lower than the average and 5 percent lower than the median salary in Seminole County.
In year 2019 Johnston Harry's salary was 59 percent lower than average Firefighter salary in the state of Florida.
| Year | 2019 |
| Full Name | Johnston Harry |
| Job Title | Firefighter |
| Get Firefighter Salary Statistics | |
| State | Florida |
| Employer | Seminole County |
| Annual Wage | $47,171 |
*Information may include where available: salary, bonuses, benefits, retirement contributions, pensions, and other financial data.
| Employer Name | Seminole County |
| Year | 2019 |
| Number of Employees | 1,347 |
| Average Annual Wage | $53,119 |
| Median Annual Wage | $49,732 |
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