University of Iowa
Gme Resident
Kavanaugh Megan Deanne in 2019 was employed at University of Iowa and had a reported pay of $1,204, according to public records.
| Year | 2019 |
| Full Name | Kavanaugh Megan Deanne |
| Original Job Title | Gme Resident 1 |
| Job Title | Gme Resident |
| Get Gme Resident Salary Statistics | |
| State | Iowa |
| Employer | University of Iowa |
| Total Pay | $1,204 |
*Information may include where available: salary, bonuses, benefits, retirement contributions, pensions, and other financial data.
| Employer Name | University of Iowa |
| Year | 2019 |
| Number of Employees | 26,537 |
| Average Annual Wage | $70,102 |
| Median Annual Wage | $55,089 |
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