University Of Florida
Chemist
Sebastian Lombardo A in 2018 was employed at University Of Florida and had a reported pay of $34,320 according to public records. This pay was 62 percent lower than the average and 44 percent lower than the median salary in University Of Florida.
University Of Florida records show Sebastian Lombardo A held job of Chemist from 2018 to 2020.
In year 2018 Sebastian Lombardo's salary was 35 percent lower than average Chemist salary in the state of Florida.
Year | 2018 |
Full Name | Sebastian Lombardo A |
Original Job Title | Chemist I |
Job Title | Chemist |
Get Chemist Salary Statistics | |
State | Florida |
Employer | University Of Florida |
Annual Wage | $34,320 |
*Information may include where available: salary, bonuses, benefits, retirement contributions, pensions, and other financial data.
Employer Name | University Of Florida |
Year | 2018 |
Number of Employees | 14,903 |
Average Annual Wage | $90,057 |
Median Annual Wage | $60,902 |
Sebastian Lombardo A (2020)Chemist | View Person Details |
Sebastian Lombardo A (2019)Chemist | View Person Details |
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