Adrian Olvera F

City Of Brownsville
Maintenance Worker

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Adrian Olvera F Overview

Adrian Olvera F in 2018 was employed at City Of Brownsville and had a reported pay of $2,446 according to public records.

City Of Brownsville records show Adrian Olvera F held job of Maintenance Worker from 2017 to 2018.

In year 2018 Adrian Olvera's salary was 93 percent lower than average Maintenance Worker salary in the state of Texas.

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Key Data

Year2018
Full NameAdrian Olvera F
Original Job TitleMaintenance Worker I
Job TitleMaintenance Worker
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StateTexas
EmployerCity Of Brownsville
Total Pay $2,446

*Information may include where available: salary, bonuses, benefits, retirement contributions, pensions, and other financial data.

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Employer

Employer NameCity Of Brownsville
Year2018
Number of Employees1,468
Average Annual Wage$40,881
Median Annual Wage$30,976
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Other records for Adrian Olvera F

 (2017)
Maintenance Worker
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Co-Workers

 (2018)
Recreation Area Leader at City Of Brownsville
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 (2018)
Library Aide at City Of Brownsville
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 (2018)
System Specialist at City Of Brownsville
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 (2018)
Lifeguard/Swimming Instructor at City Of Brownsville
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 (2018)
Library Aide at City Of Brownsville
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 (2018)
Library Aide at City Of Brownsville
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 (2018)
Library Aide at City Of Brownsville
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 (2018)
Recreation Area Leader at City Of Brownsville
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 (2018)
Recreation Area Leader at City Of Brownsville
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 (2018)
Lifeguard/Swimming Instructor at City Of Brownsville
View Person Details
Show All Employees of City Of Brownsville
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