University of Iowa
Gme Resident
David Alan Ramirez in 2024 was employed at University of Iowa and had a reported pay of $1,250, according to public records.
University of Iowa records show David Alan Ramirez held job of Gme Resident from 2020 to 2024.
| Year | 2024 |
| Full Name | David Alan Ramirez |
| Original Job Title | Gme Resident 4 |
| Job Title | Gme Resident |
| Get Gme Resident Salary Statistics | |
| State | Iowa |
| Employer | University of Iowa |
| Total Pay | $1,250 |
| Pay Plan |
*Information may include where available: salary, bonuses, benefits, retirement contributions, pensions, and other financial data.
| Employer Name | University of Iowa |
| Year | 2024 |
| Number of Employees | 28,469 |
| Average Annual Wage | $70,618 |
| Median Annual Wage | $56,847 |
David Alan Ramirez (2022)Gme Resident | View Person Details |
David Alan Ramirez (2021)Gme Resident | View Person Details |
David Alan Ramirez (2020)Gme Resident | View Person Details |
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Stephen Tofunmi Ogunnubi (2024)Adjunct Instructor at University of Iowa | View Person Details |
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Jeff Duncan D (2024)Temp Professional Employee at University of Iowa | View Person Details |
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Matthew Steven Fields (2024)Coordinator, Instructional Services at University of Iowa | View Person Details |