Osceola County
Alfred Rowlett in 2019 was employed at Osceola County and had an annual salary of $87,727, according to public records. This salary was 60 percent higher than the average and 64 percent higher than the median salary in Osceola County.
| Year | 2019 |
| Full Name | Alfred Rowlett |
| Job Title | N/A |
| State | Florida |
| Employer | Osceola County |
| Annual Wage | $87,727 |
*Information may include where available: salary, bonuses, benefits, retirement contributions, pensions, and other financial data.
| Employer Name | Osceola County |
| Year | 2019 |
| Number of Employees | 1,570 |
| Average Annual Wage | $54,759 |
| Median Annual Wage | $53,453 |
Alfred Dewitt Rowlett Jr (2023)Fire Lieutenant | View Person Details |
Alfred Dewitt Rowlett Jr (2022)Fire Lieutenant | View Person Details |
Alfred Dewitt Rowlett Jr (2021) | View Person Details |
Alfred Dewitt Rowlett Jr (2020)Fire Lieutenant | View Person Details |
Alfred Dewitt Rowlett Jr (2018)Fire Engineer | View Person Details |
Jaison Monaski (2019)Osceola County | View Person Details |
Susan Gosselin (2019)Osceola County | View Person Details |
Medina Melinda (2019)Osceola County | View Person Details |
Pearo Danver (2019)Osceola County | View Person Details |
Christopher Beeler (2019)Osceola County | View Person Details |
Bell Kyle (2019)Osceola County | View Person Details |
Moorefield Peggie-Sue (2019)Osceola County | View Person Details |
Rafael Corrada (2019)Osceola County | View Person Details |
Thomas Terance (2019)Osceola County | View Person Details |
Davis Gerald (2019)Osceola County | View Person Details |