Savage Ryan M

City of Jacksonville
Maintenance Worker

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Savage Ryan M Overview

Savage Ryan M in 2019 was employed at City of Jacksonville and had a reported pay of $31,201 according to public records. This pay was 33 percent lower than the average and 23 percent lower than the median salary in City of Jacksonville.

In year 2019 Savage Ryan's salary was 9 percent lower than average Maintenance Worker salary in the state of Florida.

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Key Data

Year2019
Full NameSavage Ryan M
Original Job TitleMaintenance Worker Ii
Job TitleMaintenance Worker
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StateFlorida
EmployerCity of Jacksonville
Annual Wage $31,201

*Information may include where available: salary, bonuses, benefits, retirement contributions, pensions, and other financial data.

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Employer

Employer NameCity of Jacksonville
Year2019
Number of Employees6,663
Average Annual Wage$46,658
Median Annual Wage$40,640
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Other records for Savage Ryan M

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