Department Of Health
Robert Seimetz J in 2015 was employed at Department Of Health and had a reported pay of $43,756 according to public records. This pay was 14 percent higher than the average and 15 percent higher than the median salary in Department Of Health.
Public records show Robert Seimetz J working for Department Of Health from 2015 to 2017.
| Year | 2015 |
| Full Name | Robert Seimetz J |
| Job Title | N/A |
| State | Florida |
| Employer | Department Of Health |
| Annual Wage | $43,756 |
*Information may include where available: salary, bonuses, benefits, retirement contributions, pensions, and other financial data.
| Employer Name | Department Of Health |
| Year | 2015 |
| Number of Employees | 3,003 |
| Average Annual Wage | $38,279 |
| Median Annual Wage | $38,189 |
Robert Seimetz J (2017) | View Person Details |
Robert Seimetz J (2016) | View Person Details |
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