Alex Gordon Sieg

University Of Iowa
Gme Resident

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Alex Gordon Sieg Overview

Alex Gordon Sieg in 2018 was employed at University Of Iowa and had a reported pay of $1,121, according to public records.

University Of Iowa records show Alex Gordon Sieg held two jobs from 2018 to 2023. From 2018 to 2020 Alex Gordon Sieg held job of Gme Resident.

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Key Data

Year2018
Full NameAlex Gordon Sieg
Original Job TitleGme Resident 1
Job TitleGme Resident
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StateIowa
EmployerUniversity Of Iowa
Total Pay $1,121

*Information may include where available: salary, bonuses, benefits, retirement contributions, pensions, and other financial data.

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Employer

Employer NameUniversity Of Iowa
Year2018
Number of Employees24,328
Average Annual Wage$63,150
Median Annual Wage$51,979
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Other records for Alex Gordon Sieg

 (2023)
Fellow Physician Accredited
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 (2022)
Fellow Physician Accredited
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 (2021)
Fellow Physician Accredited
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 (2020)
Gme Resident
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 (2019)
Gme Resident
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Highest Paid with the Same Job Title (Gme Resident)

Co-Workers

 (2018)
Gme Resident at University Of Iowa
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 (2018)
Gme Resident at University Of Iowa
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 (2018)
Gme Resident at University Of Iowa
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 (2018)
Gme Resident at University Of Iowa
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 (2018)
Gme Resident at University Of Iowa
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 (2018)
Gme Resident at University Of Iowa
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 (2018)
Gme Resident at University Of Iowa
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 (2018)
Gme Resident at University Of Iowa
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 (2018)
Gme Resident at University Of Iowa
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 (2018)
Gme Resident at University Of Iowa
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