Iowa Workforce Development
Slip Retiree
Alan Muntz W in 2018 was employed at Iowa Workforce Development and had a reported pay of $25,487, according to public records. This pay was 55 percent lower than the average and 58 percent lower than the median salary in Iowa Workforce Development.
Iowa Workforce Development records show Alan Muntz W held two jobs from 2015 to 2018.
| Year | 2018 |
| Full Name | Alan Muntz W |
| Job Title | Slip Retiree |
| Get Slip Retiree Salary Statistics | |
| State | Iowa |
| Employer | Iowa Workforce Development |
| Total Pay | $25,487 |
*Information may include where available: salary, bonuses, benefits, retirement contributions, pensions, and other financial data.
| Employer Name | Iowa Workforce Development |
| Year | 2018 |
| Number of Employees | 717 |
| Average Annual Wage | $57,047 |
| Median Annual Wage | $60,006 |
Alan Muntz W (2017)Workforce Advisor | View Person Details |
Alan Muntz W (2016)Workforce Advisor | View Person Details |
Alan Muntz W (2015)Workforce Advisor | View Person Details |
Marta Sobieszkoda M (2018)Budget Analyst at Iowa Workforce Development | View Person Details |
Jennifer Shepherd L (2018)Workforce Advisor at Iowa Workforce Development | View Person Details |
Sandy Yang Ia (2018)Revenue Examiner at Iowa Workforce Development | View Person Details |
Mary Greco F (2018)Workforce Advisor at Iowa Workforce Development | View Person Details |
Jeova Flores-alvarez S (2018)Workforce Development Manager at Iowa Workforce Development | View Person Details |
Ann Brei Johnson (2018)Information Specialist at Iowa Workforce Development | View Person Details |
Micki Mccracken K (2018)Field Auditor at Iowa Workforce Development | View Person Details |
Trudi Snyder J (2018)Training Specialist at Iowa Workforce Development | View Person Details |
Michael Nolte A (2018)Workforce Advisor at Iowa Workforce Development | View Person Details |
Lynn Angela Peterson (2018)Training Specialist at Iowa Workforce Development | View Person Details |