The average Fire Protection Inspector salary in Florida is $59,474. The average hourly pay for a Fire Protection Inspector is $28.59 per hour.
The employer paying the highest salary for a Fire Protection Inspector job in Florida is City of Sanford with an average salary as high as $59,479.
| Employer | Average Salary |
|---|---|
| City of Sanford, FL | $59,479 |
| City of Jacksonville, FL | $59,474 |
| Job Title | Average Salary |
|---|---|
| Fire Chief | $119,500 |
| Firefighter | $83,048 |
| Fire Inspector | $83,566 |
| Fire Captain | $149,359 |
| Firefighter/Emergency Medical Technician | $72,127 |
| Fire Marshal | $107,286 |
| Fire - Lieutenant | $104,340 |
| Fire Battalion Chief | $146,108 |
| Fire Fighter | $90,147 |
| Fire | $78,061 |
Select a state to view specific salary for Fire Protection Inspector and other interesting information
| State | Average Salary | Records Number |
|---|---|---|
| California | $136,247 | 1 |
| Florida | $59,475 | 15 |
| New Jersey | $56,465 | 9 |
| New York | $68,548 | 179 |
| Ohio | $63,557 | 1 |
| Virginia | $63,840 | 9 |
Select a city to view specific salary for Fire Protection Inspector in this city
| City Name | State | Records Number | Average Salary |
|---|---|---|---|
| Jacksonville | FL | 12 | $59,474 |
